42SAP Calculus

2006-04-07T12:27:00.000-07:00

Woooooooooooo there is my work tell me if it is wrong.

supplementary problems chp.8, #21

2006-04-03T18:51:00.000-07:00

alright sorry it's late but it took me a while, should have done it earlier because i have a feeling only the ridiculously hard questions were left, and they were!!! plus, it was all around not a good night for me cause i couldn't figure out how to do it so i did it all on paint, and i don't even think it's the right answer...

Question #23

2006-04-03T14:45:00.000-07:00

Excuse my terrible painting job please.

Missing 4!

2006-04-02T21:43:00.000-07:00

Okay where are the other 4? I think we need some peer pressure!
Hope you have a good review class tomorrow. Feel free to post if you have any questions!
See you soon!

Chapter 8 Supplementary Problem Numero 5 (not checked by Ms. German)

2006-04-02T20:24:00.000-07:00

Chapter 8 question 9... O_o

2006-04-02T18:26:00.000-07:00

Supplementary # 27!! Hope you like my writing =P

2006-04-02T17:47:00.000-07:00

Chapter 8 question #19

2006-04-01T11:08:00.000-08:00

Chapter 8 Supplementary Problem #3

2006-03-31T16:05:00.001-08:00

Okay, so my computer's being really weird and it won't let me put the pictures in the right order. So the first part is at the bottom. The second part is at the top. The third part is second from the bottom, and the last part is third from the bottom. Sorry about that! If anyone knows how to fix it, please let me know.

For part c), you have to split up the region into two parts as you're revolving it around the y-axis. The reason for this is that from [0,3] on the y-axis, g(x) > f(x), but from [3,4], f(x) > g(x). So you make it into two regions, evaluate each of those and add them up to get the total area.

Chapter 8 Question 13 c

2006-03-28T14:28:00.000-08:00

c.) 0 = 3t2 – 6t
t = 2,0
test t = 1, v(1) = 3(1)2 – 6(1)
v(1) = -3
test t = 3, v(3) = 3(3)2 – 6(3)
v(3) = 9
therefore, 0 <> 2 is positive
0 - (3t2 – 6t) dt
[-t3 + 3t2]
[(-(2)3 + 3(2)2) – 0]
= 4
3t2 - 6t dt
[t3 – 3t2]
[((4)3 – 3(4)2) – ((2)3 – 3(2)2)]
[16 – (-4)]
= 20
total distance traveled = 20 + 4
= 24 units

Chapter 8 Question 13 a & b

2006-03-28T14:26:00.000-08:00

Chapter 8 Question 13

a.) v(t) = 3t2- 6t
x(t) = t3- 3t2 + C
x(2) = 4
4 = (2)3 + 3(2)2 + C
4 = -4 + C
C = 8
x(t) = t3 – 3t2 + 8

b.) M(t) = 1/b-a v(t) dt
M(t) = 1/4-1 3t2 – 6t dt
M(t) = 1/3 [ t3 - 3t2 ]
M(t) = 1/3 [ ((4)3 – 3(4)2) – ((1)3-3(1)2)]
M(t) = 1/3 [64 – 48 - 1 + 3]
M(t) = 1/3 [18]
M(t) = 6
6 = 3t2 - 6t
3(t2 - 2t - 2) = 0
(-b √ (b2-4ac)) / 2a
=(-(-2) √((-2)2 – 4(1)(2))) / 2(1)
=(2 √(4 + 8)) / 2
=(2 2√3) / 2
=1 + √3, 1- √3 , [1,4]
therefore, 1 + √3

chapter 8 supplementary problem 29

2006-03-26T10:50:00.001-08:00

chapter 8 supplementary problem 29

2006-03-26T10:50:00.000-08:00

Chapter 8 Supplementary Problem #15

2006-03-26T08:54:00.000-08:00

Chapter 8 Supplementary Problem #1 c and d

2006-03-21T15:08:00.000-08:00

Chapter 8 Supplementary Problem #1 a & b

2006-03-21T14:56:00.000-08:00

Question!!

2005-12-09T22:36:00.000-08:00

Hey Ms. German, I was wondering, for #4 on the hand in assignment, it asks for the maximum and minimum, so does that mean only the global max/min, or all local max/mins? If you can, let me know, thank you, see you Monday:D

Completely stuck here!!

2005-11-18T16:09:00.000-08:00

HELP!!

Ok so I started entering the stuff for that Newton program...and I can't find the arrow key!! it looks like ->...except it's all connected. Any help would be appreciated!

Thanks!

implicit differentiation

2005-11-12T15:45:00.000-08:00

does anyone understand how to do those questions? i'm lost.

Well here is my cat in action woooo!!!!!!

2005-11-01T00:05:00.000-08:00

Thats my cat simon. He is jumping in the air after a toy i threw for him. He is like a dog trapped in a cats body. I dunno where the toy is but i knew i through it. He is so cool.

Well, why not...

2005-10-28T15:40:00.000-07:00

Brian has arrived

2005-10-28T15:12:00.000-07:00

hey i joined up, awesome dog erin

Everyone's favourite question

2005-10-28T12:37:00.000-07:00

Yes, #16 :)
So, who wants to step up and explain how to do it? Fundamental Theorem of calculus anyone? I know you're out there! (yes we will go over it on Monday too)
Have a great weekend!

dear erin s.

2005-10-27T19:45:00.000-07:00

your dog is very cute :)

2005-10-27T15:52:00.000-07:00

can i post a picture of my dog? i don't actually have a calculus question but i do have a very cute picture. i wonder if this will work.....

hullo

2005-10-26T14:34:00.000-07:00

i think your blog is lovely ms.german :)

Hmmmmmmmmmm

2005-10-26T14:22:00.000-07:00

I wonder who the "real scott" is... should I ruin it p instead of a d?
Very funny though!

hi guys

2005-10-26T14:09:00.000-07:00

hi id just like to suggest that we have a study blog party tonight that would be super.

Need Help?

2005-10-24T12:03:00.000-07:00

Try checking this out: http://apcalc.blogspot.com/
Once there look for Sarah's blog, this was the one I was showing you during class.
Wow.

Peer Help

2005-10-21T08:44:00.000-07:00

Hey! I created this blog to see if you would be interested in communicating online about calculus. You could use it to talk about the day's class, get help, discuss frustrations with topics, or give advice. Really anything you want. What do you think?